19. Spotted fur (S) in rabbits is
dominant and solid fur (s) is recessive. A pure-breeding spotted male is crossed with a
solid female. The genotypes of these individuals are? Pure breeding is another term for homozygous just as carrier (especially in sex linked problems means heterozygous). 20. The offspring of this cross would
have what appearance? The F1 offspring are all
Ss. Since they all contain one S allele (the dominant allelic form), all the offspring
will exhibit the dominant trait, spotted fur. When you work a problem like this, it
is a good idea to put a legend at the top of your page so you don't get the dominant trait
and recessive trait confused (especially a possibility if both descriptions start with the
same letter as they so in this problem!). Thus, before I attempted to answer this
question, I would have at the top of my work the following : 21. Two of these F1
offspring mate. The genotypic ratio of the offspring from this cross would be Remember that the F1 offspring are all Ss. Thus, the work to arrive at the answer should look like this: genotypes of the parents of this cross: Ss X Ss gametes that each parent can produce: S and s Punnett square:
Note that the gametes produced by each parent are written at the top ( S and s by one parent) and along the left side (also S and s by the other parent). The possible types of offspring are found in the squares below and to the right of the gametes. One can readily determine that these are the gametes produced by the fusion of an egg cell and sperm cell because the offspring are diploid. They each have two genes for coat color. Remember, these are the theoretical results. It does not mean that if four offspring were produced by this cross, three would have spotted fur and one would have solid fur ( the expected phenotypic ratio).
Use
the Punnett square to answer the question asked: |
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